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145=6x^2-x
We move all terms to the left:
145-(6x^2-x)=0
We get rid of parentheses
-6x^2+x+145=0
a = -6; b = 1; c = +145;
Δ = b2-4ac
Δ = 12-4·(-6)·145
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-59}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+59}{2*-6}=\frac{58}{-12} =-4+5/6 $
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